If you have four 100-ohm resistors in parallel, what is the load?

When resistors are connected in parallel, the total or equivalent resistance can be calculated using the formula:

[

\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4}

]

In this scenario, you have four 100-ohm resistors, which means:

[

\frac{1}{R_{total}} = \frac{1}{100} + \frac{1}{100} + \frac{1}{100} + \frac{1}{100}

]

Simplifying this sum gives:

[

\frac{1}{R_{total}} = \frac{4}{100} = \frac{1}{25}

]

To find (R_{total}), you take the reciprocal:

[

R_{total} = 25 \text{ ohms}

]

Thus, when four 100-ohm resistors are connected in parallel, the overall resistance or load is effectively reduced to 25 ohms. This reduction is because the paths for the current through each resistor provide multiple routes, allowing more current to flow